A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
We know that a charge moving in a magnetic field is subject to the force:
F = q · v · B
But we also know that:
F = m · a
Therefore, it must be:
m · a = <span>q · v · B
And solving for a:
</span>a = <span>q · v · B / m
Recall that for a proton:
q = 1.6</span>×10⁻¹⁹ C
m = 1.673×10⁻²⁷ kg
Now, you can find:
a = 1.6×10⁻¹⁹ · 7.0 · 1.7 / <span>1.673×10⁻²⁷
= 1.14</span>×10⁹ m/s²
Hence, the acceleration of the proton is 1.14<span>×10⁹ m/s²</span>.
Answer: The answer position may vary. But the correct answer is D. No; Raul changes more than one variable so the results will be invalid.
Explanation:
Raul's experimental set-up will not produce valid results because he intends to change more than one variable.
One variable that Raul will change is the pot size. According to the description, however, Raul will also change one other variable—the type of flower that is planted. Even though Raul plans on using flowers only, he should use the same type of flower in each pot, not different types.
Valid results are only produced when only one variable is changed at a time.
Answer:
The thickness of the oil slick is 
Explanation:
Given that,
Index of refraction = 1.28
Wave length = 500 nm
Order m = 1
We need to calculate the thickness of oil slick
Using formula of thickness
Where, n = Index of refraction
t = thickness
= wavelength
Put the value into the formula
Hence, The thickness of the oil slick is
Answer:
Work is the change in energy and power is the rate of doing work.
