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V125BC [204]
4 years ago
15

Two wooden boxes of equal mass but different density are held beneath the surface of a large container of water. Box A has a sma

ller average density than box B. When the boxes are released, they accelerate upward to the surface. Which box has the greater acceleration?
(A) It depends on the cotent of the boxes
(B) Box B
(C) They are the same
(D) We need to know the actual densities of the boxes in order to answer the question
(E) Box A
Physics
1 answer:
sweet [91]4 years ago
4 0

Answer:

As a box A has a smaller average density than box B, then it will have a greater acceleraton towards the surface upon releasing. So the option E) Box A is a correct option.

Explanation:

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A car takes 10 s to go from vi=0 m/s to vf=25 m/s. How far does the car travel in<br> that time?
SSSSS [86.1K]

Answer:

2.5 k

Explanation:

8 0
3 years ago
If a steel cylindrical specimen is stressed nominally to 53 MPa, what stress level exists at the tip of an elliptical surface fl
ElenaW [278]

Answer:

227.9MPa

Explanation:

Length of the flaws is given by

2b = 5.8microns

b = 2.9 × 10⁻⁶m

The relation between the radius of curvature and length and width of the elliptical flaw

r = \frac{a^2}{b}

a = \sqrt{rb}

Equation for stress at the tip of an elliptical surface flaw

\sigma _t = \sigma(1 + 2\frac{b}{a}  )\\\\\sigma _t = \sigma(1 + 2\frac{b}{\sqrt{rb} })\\\\\sigma _t = \sigma(1 + 2\frac{\sqrt{b} }{\sqrt{r} })\\\\\sigma _t = \sigma(1 + 2\sqrt{\frac{b}{r} })

\sigma _t = 53 \times 10^6 (1 + 2\sqrt{\frac{2.9\times10^-^6 }{1065 \times 10^-^9} } \\\\\sigma _t = 227.9 \times 10^6\\\\\sigma _t  = 227.9MPa

4 0
3 years ago
If a 0.200-kilogram ball sits on a shelf 2.00 meters from the floor, how much mechanical energy (me) does it possess? More than
iogann1982 [59]

Answer:

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exactly 3.92 j

Explanation:

As we know that mechanical energy is sum of kinetic energy and potential energy of the system

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Since ball is at rest so kinetic energy of the ball must be ZERO

Now for potential energy we know that

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now we know

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5 0
3 years ago
I need help getting started with number 8.
ratelena [41]

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Displacement = 5m, in the negative direction.

In #9 . . . distance will be the same.  Displacement is going to be the same magnitude, but in the positive direction.

This is so simple that it's hard to talk about.  

In #8, "What was the bug's distance ?". "Distance was 5 meters.".  "What was the bug's displacement ?", "Displacement was 5 meters backwards."

In #9, What was the bug's distance ?". "Distance was 5 meters.".  "What was the bug's displacement ?", "Displacement was 5 meters forward."

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