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2 years ago

What boolean operation does the circuit compute?

1 answer:

8 0

A circuit computes various types of Boolean operations. As in the question no specific circuit has been shown,so we have to know the fundamental logic operations.

Out of the various types of logic operations in Boolean algebra,the simple operations are- addition,subtractions,multiplications,division through logic gates.

Various logic or Boolean operations are NOT GATE,OR GATE ,AND GATE .

There are other operations also like NAND GATE,NOR GATE and XOR GATE etc

NOT gate is the simple logic gate which inverts one quantity.it makes 1[high] to 0[low] and vice versa.

OR gate gives 1 [high] when one of the input is 1 and low when all the inputs are low.

AND operation gives 1 when all the inputs are high and low when one of the input is low

NAND operation is AND gate followed by a NOT gate

NOR operation is the OR gate followed by a NOT gate.

Remembering these simple rules we can get the idea of the operations involved in the circuit. Each circuit has different symbols and gives different results.

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In a nuclear power plant, nuclear energy is first changed to ? energy

MakcuM [25]

Thermal energy Thermal energy Thermal energy

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2 years ago

A 0.29 kg particle moves in an xy plane according to x(t) = - 19 + 1 t - 3 t3 and y(t) = 20 + 7 t - 9 t2, with x and y in meters

Artist 52 [7]

Answer:

Part a)

$F = 7.76 N$

Part b)

$\theta = -137.7 degree$

Part c)

$\theta = -127.7 degree$

Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

$x = -19 + t - 3t^3$

$y = 20 + 7t - 9t^2$

Part a)

differentiate x and y two times with respect to time to find the acceleration

$a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)$

$a_x = \frac{d}{dt}(0 +1 - 9t^2)$

$a_x = -18t$

$a_y = \frac{d^2}{dt^2}(20 + 7t - 9t^2)$

$a_y = \frac{d}{dt}(0 +7 - 18t)$

$a_y = -18$

Now the acceleration of the object is given as

$\vec a = (-18t)\hat i + (-18)\hat j$

at t= 1.1 s we have

$\vec a = -19.8 \hat i - 18 \hat j$

now the net force of the object is given as

$\vec F = m\vec a$

$\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)$

$\vec F = -5.74 \hat i - 5.22 \hat j$

now magnitude of the force will be

$F = \sqrt{5.74^2 + 5.22^2} = 7.76 N$

Part b)

Direction of the force is given as

$tan\theta = \frac{F_y}{F_x}$

$tan\theta = \frac{-5.22}{-5.74}$

$\theta = -137.7 degree$

Part c)

For velocity of the particle we have

$v_x = \frac{dx}[dt}$

$v_x = (0 +1 - 9t^2)$

$v_y = \frac{dy}{dt}$

$v_y = (0 +7 - 18t)$

now at t = 1.1 s

$\vec v = -9.89\hat i - 12.8 \hat j$

now the direction of the velocity is given as

$\theta = tan^{-1}(\frac{v_y}{v_x})$

$\theta = tan^{-1}(\frac{-12.8}{-9.89})$

$\theta = -127.7 degree$

7 0

2 years ago

The sediment deposited by glaciers is called __________ .

nalin [4]

Answer:

The sediment deposited by glaciers is called Glacial deposition.

3 0

2 years ago

An object that completes 20 vibrations in 10 seconds has a frequency of

nika2105 [10]

Answer:

The object has frequency of 2 Hz and time period of 0.5 s.

Explanation:

Frequency is defined as number of oscillation per second ie back and forth swings done in single second.

Here it is given that the object oscillates 20 times in 10 seconds.

So f = $\frac{20}{10}$ = 2Hz

The time period is defined as time taken by the object to complete one full oscillation.

T = $\frac{1}{f}$

T= $\frac{1}{2}$ =0.5 s

Thus the object has frequency of 2 Hz and time period of 0.5 s.

7 0

2 years ago

If there was no frictional force acting on the ball in question 2 what would happen to the player? Use inertia and Newton’s 1st

laila [671]

Newwton's law of inertia states that an object will not be able to move unless force is applied to it

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2 years ago