All categories

3 years ago

Without graphing, determine the domain.

Mathematics

1 answer:

adoni [48]3 years ago

6 0

#5 - Domain - (−∞,∞),{x|x∈R}

#5 - Range - [3,∞),{y|y≥3}

#6 Domain - (−∞,9],{x|x≤9}

#6 Range - [0,∞),{y|y≥0}

Hope This Help's !!

You might be interested in

Here are four questions A) 2/5 B) 2/3 C) 1/4 D) 1/10 put them in order

lara [203]

Answer:

1/10, 1/4, 2/5, 2/3.

Step-by-step explanation:

Convert the fractions into decimals.

2/5 = 0.4

2/3 ≈ 0.66666

1/4 = 0.25

1/10 = 0.1

Arrange from smallest to largest.

0.1, 0.25, 0.4, 0.6666

Change back to fraction form.

1/10, 1/4, 2/5, 2/3.

3 0

3 years ago

Read 2 more answers

Which of the following expressions is equal to tan245°?

givi [52]

Answer:

tan65°

Step-by-step explanation:

4 0

3 years ago

I need help with this please help me

Tatiana [17]

Answer:last one

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which angle has a sine of -1/2 and a cosine of -√3/2

Sergeeva-Olga [200]

$\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)$

$\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}$

$\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}$

$x\in(180^o;\ 270^o)\ therefore\ \boxed{x=30^o+180^o=210^o}$

8 0

3 years ago

The length of a rectangle is 8 inches longer than half of its width.The area of the rectangle is 18 square inches.How many inche

SOVA2 [1]

Answer:

The correct answer is 2 inches.

Step-by-step explanation:

Let l inches and w inches be the length and width of a rectangle respectively.

According to the given problem, l - 8 = $\frac{w}{2}$ .

Area of the rectangle is given to be, according to the question, 18 square inches.

Thus l × w = 18

⇒ l × (2l - 16) = 18

⇒ 2 $l^{2}$ - 16l - 18 = 0

⇒ $l^{2}$ - 8l - 9 = 0

⇒ ( l - 9) ( l + 1) = 0

The possible values of l are 9 and -1. As the length cannot be equal to -1, thus the value of the length is 9 inches.

Width of the rectangle is 2 inches.

5 0

3 years ago

Without graphing, determine the domain.​

Without graphing, determine the domain.