Answer:
B
Step-by-step explanation:
CORRECT 100%!!!!!!!!!!!!!!!
<u>Answer:</u>
Annual Income of A=
and
Annual Income of B=
<u>Step-by-step explanation:</u>
<u>Given Data:</u>
Ratio of annual income of A and B=4:3
Ratio of expenditures of A and B=3:2
Saving of A and B=1000
<u>Required:</u> Annual Income of A and B=?
<u>Solution:</u>
If ratio of income of A and B is 4:3
then let Income of A=
and Income of B=
If ratio of expenditure of A and B is 3:2
then let expenditure of A=
and expenditure of B=
Therefore,
...........
and
..........
subtracting Eq(1) and Eq(2), we get


putting
in Eq(1), we get value of
as

because x and y are equal in Eq (3)
Now, Annual Income of A=
and Annual Income of B=
10% chance of burning out
100-10= 90% chance of not burning out
90% = 0.9
3 lightbulbs
0.9^3 = 0.729 = 72.9%
The probability that all 3 lightbulbs stay lit by the end of the month is 72.9%
i'm pretty sure it would be 143 but i'm not entirely sure
Answer: 143
Answer:
.....................................
Step-by-step explanation: