Answer:
650 mmol.
Explanation:
The equation for the fermentation of one mole of glucose is:
C₆H₁₂O₆ + 2 NAD⁺ + 2 ADP + 2 P i + 2 NADH → 2 EtOH + 2 ATP + 2 NADH + 2 NAD⁺
Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:
C₆H₁₂O₆ + 2 ADP + 2 P i → 2 EtOH + 2 ATP
With the equation, we calculate the maximum amount of ethanol that could be obtained theoretically:
1000 mmol C₆H₁₂O₆ ------------ 2000 mmol EtOH
325 mmol C₆H₁₂O₆ ------------- x= 650 mmol EtOH
Therefore, the maximum amount of ethanol that could be produced is 650 mmol.
The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
Answer:
820.864 g
Explanation:
1) The atomic mass of sulfur (found from the periodic table) is 32.065 amu. Use this mass to find the molar mass of Sulfur. Sulfur is S8 so the molar mass of sulfur is:
8 × 32.065 = 256.52 g/mol
2) To find the mass use the formula:
m = n × M where <em>m</em><em> </em>is the mass, <em>n</em><em> </em>is the number of moles, and <em>M</em><em> </em>is the molar mass.
3)
Answer:
Molar mass of Na2HPO4=141.96, of Na2HPO4. 12H2O = 358.14: so to get the same 0.4 M: 28.65/358.14*141.96 g, add water until you reach 200ml , dissolve all solid and then filter to make sterile.
Explanation:
