Answer:
I don't <u>understand</u><u> </u><u>your</u><u> </u><u>question</u><u> </u>
We call these reactive elements, becausethese atoms really like to follow the buddysystem and form bonds with other atoms.Noble gases, however, don't have thisproblem. Their outer shells are filled to the max, so they don't need to bond or react with any other atoms.
Answer:
Atoms=9.033*10^23 atoms
Explanation:
Atoms=no.of miles*Avogadro's no.
Atoms=1.5*6.022*10^23
Atoms=9.033*10^23 atoms
Answer:
53.6 g of N₂H₄
Explanation:
The begining is in the reaction:
N₂(g) + 2H₂(g) → N₂H₄(l)
We determine the moles of each reactant:
59.20 g / 28.01 g/mol = 2.11 moles of nitrogen
6.750 g / 2.016 g/mol = 3.35 moles of H₂
1 mol of N₂ react to 2 moles of H₂
Our 2.11 moles of N₂ may react to (2.11 . 2) /1 = 4.22 moles of H₂, but we only have 3.35 moles. The hydrogen is the limiting reactant.
2 moles of H₂ produce at 100 % yield, 1 mol of hydrazine
Then, 3.35 moles, may produce (3.35 . 1)/2 = 1.67 moles of N₂H₄
Let's convert the moles to mass:
1.67 mol . 32.05 g/mol = 53.6 g
Elements in the same group have D. Same number of valence electrons.