In chemistry, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.
Answer:
Sharing or covalent bonding is taking place.
Explanation:
The valence electron will be shared by both the atoms so that means that the election will move around both of the atoms.
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Answer:
9.24% the percent of Mg in the mixture.
Explanation:
Mass of silver bromide = 1.1739 g
Moles of silver bromide = ![\frac{1.1739 g}{188 g/mol}=0.006244 mol](https://tex.z-dn.net/?f=%5Cfrac%7B1.1739%20g%7D%7B188%20g%2Fmol%7D%3D0.006244%20mol)
1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.
Moles of bromine atoms = 0.006244 moles
Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :
![\frac{0.006244 mol}{2}=0.003122 mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.006244%20mol%7D%7B2%7D%3D0.003122%20mol)
Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :
magnesium atom
Mass of 0.003122 moles of magnesium :
0.003122 mol × 24 g/mol = 0.07493 g
Mass of the sample = 0.8107 g
Percentage of magnesium in the sample ;
![=\frac{0.07493 g}{0.8107 g}\times 100=9.24\%](https://tex.z-dn.net/?f=%3D%5Cfrac%7B0.07493%20g%7D%7B0.8107%20g%7D%5Ctimes%20100%3D9.24%5C%25)
9.24% the percent of Mg in the mixture.