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3 years ago

I’m a small library, there are 5 nonfiction books. There are 130 nonfiction books. How many fiction books are there?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

5 0

Answer: 125 fiction books

Aleksandr [31]3 years ago

3 0

Answer:

i think this qestion in written wrong

Step-by-step explanation:

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5n + 3/4n = 2<br> Solve for n

vovangra [49]

5n+3/4n=2
20n+3n/4=2
23n/4=2
23n=8
n=8/23

3 0

3 years ago

Read 2 more answers

A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi

MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force $F=116 N$

Increase in Kinetic Energy $\Delta K.E.=30 J$

Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

$\Delta K.E.=W_g+W_f+W_N$

$30=W_g-F\cdot d$

$30=W_g-116\cdot 1.9$

$W_g=250.4 J$

(b)In absence of applied force thus

work done by gravity will be equal to change in kinetic Energy

change in Kinetic Energy $=210 J$

6 0

3 years ago

Help me find that greatest common factor please. Thanks!

sweet [91]

The gcf of -18m and 27 is -9 if not then positive 9, but if you want me to also solve the equation its -18m + 27 is -9(2m - 3) i hope it helps!

3 0

2 years ago

What does it mean when two lines are perpendicular? What does it tell you about the equations?

Vaselesa [24]

When lines are perpendicular it’s called parallel, it’s when the lines never touch

3 0

3 years ago

Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and

Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437$

P(sample average sediment density is at most 3.00)

$P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)$

Calculation the value from standard normal z table, we have,

$P(x \leq 3.00) = 0.918$

0.918 is the probability that the sample average sediment density is at most 3.00

4 0

3 years ago