-- Start with 86.
-- Subtract 9 the first time. You have 77 left.
-- Subtract 9 the 2nd time. You have 68 left.
-- Subtract 9 the 3rd time. You have 59 left.
-- Subtract 9 the 4th time. You have 50 left.
-- Subtract 9 the 5th time. You have 41 left.
-- Subtract 9 the 6th time. You have 32 left.
-- Subtract 9 the 7th time. You have 23 left.
-- Subtract 9 the 8th time. You have 14 left.
-- Subtract 9 the 9th time. You only have 5 left, so you can't subtract 9 again.
You subtracted it 9 times, and you have 5 left.
So 86 divided by 9 is (9 with remainder 5) .
Answer:
29 ; 37
Step-by-step explanation:
The figure is composed by a square, a rectangle, and a right triangle
The perimeter of the square is 6 units
The perimeter of the rectangle is 10 units
The triangle is composed by a side of 6 units and a side of 5 units
The third side can be find with the Pythagorean theorem
= 7,81025
The total perimeter is
6 + 10 + 5 + 7,81025 = 28,81025 = 29
Area of the square = 2^2 = 4 square units
Area of the rectangle = 6 x 3 = 18 square units
Area of the triangle = (5 x 6)/2 = 15 square units
Total area = 4 + 18 + 15 = 37 square units
Answer:
y = mx + b
Step-by-step explanation:
Use that form to find the slope.
Answer:
i think its top right i am not sure
Step-by-step explanation
looks right to me
To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
