Question

The power line can be described by the equation shown below:

Answer 1

Answer:

$\begin{array}{cc}x&y\\ \\-2&-1\\0&-2\\2&-3\\6&-5\\9&-6.5\end{array}$

Step-by-step explanation:

Given:

$y=-\dfrac{1}{2}x-2$

First, find y for given x:

When x = 0, then

$y=-\dfrac{1}{2}\cdot 0-2\\ \\y=-2$

When x = 6, then

$y=-\dfrac{1}{2}\cdot 6-2\\ \\y=-3-2\\ \\y=-5$

When x = 9, then

$y=-\dfrac{1}{2}\cdot 9-2\\ \\y=-4.5-2\\ \\y=-6.5$

Now find x for given y:

When y = -1, then

$-1=-\dfrac{1}{2}x-2\\ \\-1+2=-\dfrac{1}{2}x\\ \\1=-\dfrac{1}{2}x\\ \\-2=x\\ \\x=-2$

When y = -3, then

$-3=-\dfrac{1}{2}x-2\\ \\-3+2=-\dfrac{1}{2}x\\ \\-1=-\dfrac{1}{2}x\\ \\2=x\\ \\x=2$

So, the table is

$\begin{array}{cc}x&y\\ \\-2&-1\\0&-2\\2&-3\\6&-5\\9&-6.5\end{array}$