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lubasha [3.4K]
3 years ago
13

Marilyn has a bag of coins. The bag contains 25 wheat pennines, 15 Canadian pennies, 5 steel pennies, and 5 Lincoln pennies. She

picks a coin randomly from the bag. What is the probability that she picked a steel penny or a lincoln penny? A.) 10% B.) 20% C.) 50% D.) 30%​
Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

B

Step-by-step explanation:

In probability, "AND" means to multiply and "OR" means to add.

Here they want probability of steel penny ( P(s) ) "OR" probability of lincoln penny ( P(l) ).

Let's find the individual probabilities and "ADD" them.

P(s) = 5/50 (since there are 5 steel pennies and there are 50 coins in total)

P(l) = 5/50 (since there are 5 lincoln pennies and there are 50 coins in total)

So probability of 5 steel penny and 5 lincoln penny = 5/50 + 5/50 = 10/50 = 1/5

1/5 is equal to 20%, correct answer is B

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Evaluate the expression
nadezda [96]

Answer:

32

Step-by-step explanation:

We are given the expression:

\frac{-8(13-37)}{6}

and asked to evaluate the expression.

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.

Solve inside the parentheses first. Subtract 37 from 13.

⇒ 13-37= -24

\frac{-8(-24 )}{6}

Next, multiply -8 and -24.

⇒ -8*-24= 192

\frac{192}{6}

Finally. divide 192 by 6.

⇒ 192/6 = 32

32

When evaluated, the expression -8(13-37)/6 is equal to 32.

8 0
2 years ago
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In a manufacturing process, a machine produces bolts that have an average length of 5 inches with a variance of .08. If we rando
xz_007 [3.2K]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And replacing:

\mu_{\bar X}= 5

And the deviation:

\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126

And the distribution is given:

\bar X \sim N(\mu= 0.08, \sigma= 0.126)

Step-by-step explanation:

For this case we have the following info given :

\mu= 5. \sigma^2 =0.08

And the deviation would be \sigma = \sqrt{0.08}= 0.283

For this case we select a sample size of n = 5 and the distirbution for the sample mean would be:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And replacing:

\mu_{\bar X}= 5

And the deviation:

\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126

And the distribution is given:

\bar X \sim N(\mu= 0.08, \sigma= 0.126)

4 0
3 years ago
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Answer:

y-3= 2(x-1)

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1. The equation of a line in point slope form is y-y1= m(x-x1)

2. m=slope and (x1,y1) is the point the line passes through

3. The point the line passes through is (1,3)

4, The slope is 2

5. Therefore the answer is y-3=2(x-1)

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Answer:

ℎℎ ℎ

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