The answer is: b - lies in quadrant II when graphed.
Explanation:
Any number less than zero is a negative number.
Example: -1
Any number greater than zero is a positive number.
Example: 1
(a, f(a))
(-1,1)
When these example points are graphed, they are placed in the second quadrant.
Answer:
Step-by-step explanation:
a = 2, b = 1, c = -3
We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.
a * c = 6 and the factors of 6 and 1 and 6, 2 and 3. Well, 6 - 1 doesn't equal 1 and neither does 6 + 1. So our factors are 3 and 2. In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1. That means that 3 is positive and 2 is negative. Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):
![2x^2+3x-2x-3=0](https://tex.z-dn.net/?f=2x%5E2%2B3x-2x-3%3D0)
Group the first 2 terms together and the second 2 term together in order to factor:
and factor out what's common in each set of parenthesis.
![x(2x+3)-1(2x+3)=0](https://tex.z-dn.net/?f=x%282x%2B3%29-1%282x%2B3%29%3D0)
Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with. We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same. Ours are identical: (2x + 3). That is common now, and can be factored out:
![(2x+3)(x-1)=0](https://tex.z-dn.net/?f=%282x%2B3%29%28x-1%29%3D0)
That matches your first choice
Answer:
25%
Step-by-step explanation:
The percent of increase can be calculated using following formula:
![\text{Percent Increase}=\dfrac{\text{Final Amount-Initial Amount}}{\text{Initial Amount}}\cdot 100\%.](https://tex.z-dn.net/?f=%5Ctext%7BPercent%20Increase%7D%3D%5Cdfrac%7B%5Ctext%7BFinal%20Amount-Initial%20Amount%7D%7D%7B%5Ctext%7BInitial%20Amount%7D%7D%5Ccdot%20100%5C%25.)
In your case,
- Initial amount = 12 students;
- Final amount = 15 students,
then
![\text{Percent Increase}=\dfrac{15-12}{12}\cdot 100\%=\dfrac{3}{12}\cdot 100\%=\dfrac{1}{4}\cdot 100\%=25\%.](https://tex.z-dn.net/?f=%5Ctext%7BPercent%20Increase%7D%3D%5Cdfrac%7B15-12%7D%7B12%7D%5Ccdot%20100%5C%25%3D%5Cdfrac%7B3%7D%7B12%7D%5Ccdot%20100%5C%25%3D%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20100%5C%25%3D25%5C%25.)
Answer:
Step-by-step explanation:
Thank you for providing the details of the question.
Unfortunately none of the results you have to choose from will give you 44%
The problem resembles the first probability question you were likely asked. "What is the probability of getting a heads on every throw of a fair coin?" The answer is 1/2 no matter how many times you throw the coin or what has happened before any point in the throws.
The answer should be 6/50. If this turns out not to be the answer and you have an instructor your safest course of action is to ask how 44% was obtained. Tell me in a comment.
The answer to this question is C because all the other answers have a variable which will always have an answer beside it