Ask question

Ask question

All categories

3 years ago

7

please help. No links or fake answers. If your going to answer, may you please do one screenshot at the least. Thank you for you

r time.

1 answer:

Lady bird [3.3K]3 years ago

7 0

Answer:

29

Step-by-step explanation:

You might be interested in

Evaluate (3)^1/6 × (3)^-2/3

Elan Coil [88]

39918656718818881883

7 0

2 years ago

Read 2 more answers

Phillip wanted to leave a 15% tip. Phillip's bill was $36.00. How much will he leave for a tip?

Anastaziya [24]

Your answer would be letter B. $5.40

4 0

3 years ago

Read 2 more answers

H(t)=t^4+3t^2-t+3<br> h'?

Natalija [7]

Answer: $h'(t)=4t^3 + 6t-1$

Step-by-step explanation:

Use the power rule for differentiation.

6 0

2 years ago

Pls helpppppp!! before 12!

NISA [10]

<em>The answer is 25.12 exactly</em>

5 0

3 years ago

Read 2 more answers

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago