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2 years ago

6

Bren has a deck of cards. As shown below, each card is labeled with a rule describing a pattern in a sequence.select a card and

decide on a starting number. Use the rule to write the first five terms in your sequence. Add 1.6 Add 0.33 add 6.5 Add 0.25 Add 1.15

2 answers:

kirza4 [7]2 years ago

6 0

Answer:1

Step-by-step explanation:

Aleksandr [31]2 years ago

6 0

Answer is 1 jajjaakaoalawlwlkwjwbwbwwbwbwbww

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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

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3 years ago

Graph the function f(x) = -1/4 x - 2 <br><br>just tell me the points

cupoosta [38]

Two points are (0,-2) and (400,-102).

8 0

3 years ago

Can someone help me with this

Solnce55 [7]

Aye man , who wants to give me points

4 0

2 years ago

For his phone service, Tom pays a monthly fee of $28, and he pays an additional $0.04 per minute of use. The least he has been c

Len [333]

Answer:

1421 minutes

Step-by-step explanation:

(84.48-28)/.04=M

84.48-28=56.48

56.48/.04=1421

6 0

3 years ago

PLEASE! ANSWER THIS! HELP! PLEASE!!!!!!!!!!!!!! <br><br>c. Expand: (tan(theta) - 1)^3

jonny [76]

Answer:

(tan(theta)-1)^3

= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)

= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)

= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1

= tan^3(theta)-3tan^2(theta)+3tan(theta)-1

Hope this helps :)

6 0

2 years ago