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Goryan [66]
3 years ago
9

Explain how to draw a box and whisker plot of the data below 33,42,18,13,8,26,42,47,28,22,35,13,29,20,39,37,10

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0
  1. Put all of these numbers in order 8, 10, 13, 13, 18, 20, 22, 26, 28, 29, 33, 35, 37, 39, 42, 42, 47
  2. Find which number is in the middle (28)
  3. On each side of the middle number find the middle of those (15.5 and 38 respectively)
  4. Make the box and whisker plot minimum at 8, start box at 15.5, line in box at 28, end box at 38, and end plot at 47
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Which value is a solution to the inequality x – 4 > 15.5?
Alex Ar [27]

Answer:

x>19.5

Step-by-step explanation:

Let's solve your inequality step-by-step.

x−4>15.5

Step 1: Add 4 to both sides.

x−4+4>15.5+4

x>19.5

Answer:

x>19.5

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Write the equation of a rational function g(x) with vertical asymptotes at x = -3 and x = 3 , a horizontal asymptote at y = -4 a
Bezzdna [24]

Answer:

The equation for rational function for given asymptotes is

f(x)=(-4x^2-6)/{(x-3)(x+3)}

Step-by-step explanation:

Given:

vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at

y=-4 i.e parallel  to x axis.

To find:

equation of a rational function i.e function in form p/q

Solution;

the equation should be in form of p/q

Numerator :denominator.

Consider f(x)=g(x)/h(x)

as vertical asymptote are x=-3 and x=3

denominator becomes, (x-3) and (x+3)

for horizontal asymptote to exist there should have same degrees  in numerator and denominator which of '2'

when g(x) will be degree '2' with -4 as coefficient and dont have  any real.

zero.

By horizontal asymptote  will be (-4x^2 -6)

The rational function is given by

f(x)=g(x)/h(x)

={(-4x^2-6)/(x-3)(x+3)}.

3 0
3 years ago
Ted brought a cooler containing 7.5 liters of water to a picnic. If 500 milliliters of water are served to each person, how many
bekas [8.4K]
Answers:
k = 13The smallest zero or root is x = -10
===============================
Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
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It could be done with two boxes how big is it
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