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2 years ago

6.) Which trigonometric function is equal to Cos 84°?

Mathematics

1 answer:

lidiya [134]2 years ago

5 0

It's sin 6 .....so b is the answer !

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

2 years ago

Need help with this

Zigmanuir [339]

In the ones place its 1

hundreds = 5
thaosands = 4

3 0

3 years ago

Find the area and perimeter of the rectangle Length = 5cm Breadth =2cm

avanturin [10]

Answer:

perimeter: 14

Area: 10

Step-by-step explanation:

PERIMETER

2x(L+B) = 2x(5+2) = 2x(7) = 14

AREA

LxB = 5x2 = 10

PLEASE MARK ME BRAINLIEST

5 0

3 years ago

Rewrite the equation by completing the square.

ser-zykov [4K]

Answer:

4 × 2 + 20×

Step-by-step explanation:

please your questions are mixed up

4 0

3 years ago

Anyone know the answer?

balu736 [363]

Answer:

segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B C .

5 0

2 years ago