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2 years ago

How many didgidts of pi are there? Write it no copy n pastin

Mathematics

1 answer:

igomit [66]2 years ago

8 0

Answer:

There are 32 digits in pi.

Step-by-step explanation:

Pi is represented as:

$\pi$ or 3.1415926535897932384626433832795 which is commonly rounded to 3.14.

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Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?

Cerrena [4.2K]

2 occurred 3times

$\\ \sf\longmapsto S=6\times 3=18$

$\\ \sf\longmapsto |S|=18$

Now

$\\ \sf\longmapsto E=No\:of\:times\: 2\:occured$

$\\ \sf\longmapsto |E|=3$

we know

$\boxed{\sf P(E)=\dfrac{|E|}{|S|}}$

$\\ \sf\longmapsto P(E)=\dfrac{3}{18}$

$\\ \sf\longmapsto P(E)=\dfrac{1}{6}$

6 0

3 years ago

Free points

elena-14-01-66 [18.8K]

Answer:

10932

2959

Step-by-step explanation:

5 0

3 years ago

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goldfiish [28.3K]

Answer:

250

Step-by-step explanation:

There is a 200 start up cost plus 50 per month

Cost = 200 + 50m where m is the number of months

We have 1 month

Cost = 200 +50(1)

Cost = 250

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2 years ago

Read 2 more answers

PLEASE, I NEED HELP WITH THIS QUESTION!!!!

Usimov [2.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int

meriva

Answer:

b) 95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14

sample standard deviation 'S' = 9.3

95 percent confidence interval for this single-sample t test

The values are $(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })$ the 95 percent confidence interval for the population mean 'μ'

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

$(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })$

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

Conclusion:-

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

6 0

3 years ago