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olya-2409 [2.1K]
3 years ago
11

108t^2-60t factor the polynomial

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0
Factor out 12t to get 12t(9t-5)
You might be interested in
30 POINTS HELP PLEASE
Reptile [31]

Answer:

\large\boxed{a=-3,\ b=-7\ and\ c=3}

Step-by-step explanation:

ax^2+bx+c=0

We have:

-3a^2=7a-3          <em> subtract 7a from both sides</em>

-3a^2-7a=7a-7a-3

-3a^2-7a=-3           <em>add 3 to both sides</em>

-3a^2-7a+3=-3+3\\\\-3a^2-7a+3=0\to a=-3,\ b=-7, c=3

8 0
3 years ago
Your equation:<br><img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B%3F%7D%20%20%5Ctimes%20%20%7B3%7D%5E%7B%3F%7D%20%20%5Cdiv%20
Alisiya [41]
3^1x3^1/3^1=3


Steps

3x1=3
3x1=3
3/3=3

Hope that helps
7 0
3 years ago
An investment grows by 3% per year for 20 years. By what percent does it increase over the 20 year period?
Y_Kistochka [10]
3%?? The question doesn't make much sense.
7 0
4 years ago
Let fx) = 8x-3<br> What is (5)?<br> O A. 40<br> O B. 37<br> O C. 45<br> O D. 43
saveliy_v [14]

Answer:

I'm not sure i think B. 37

Step-by-step explanation:

f(x) = 8x-3

f(5)= 8(5)-3

40-3=37

8 0
3 years ago
How to do this question plz answer me ​
Sati [7]

Answer:

d =  \frac{4 - 3c}{c + 1}

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

c =  \frac{4 - d}{d + 3}

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

c(d + 3) = 4 - d

<em>Expand</em><em>:</em>

<em>cd + 3c = 4 - d</em>

<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

cd + d = 4 - 3c

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>

<em>d(c + 1) = 4 - 3c</em>

<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

<em>d =  \frac{4 - 3c}{c + 1}</em>

7 0
3 years ago
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