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3 years ago

X² + 5 Given g(x) = 2x - 3, 11, x = 6 2 < x < 6, x < 2 find g(5)

Mathematics

1 answer:

zvonat [6]3 years ago

5 0

Step-by-step explanation:

uhm you know the excrotery system to the factor

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Evaluate 5−44⋅(−0.75)−18÷23⋅0.8−45.

REY [17]

Answer:

-7.62

Step-by-step explanation:

Using BODMAS rule: Bracket of division,multiplication, addition and subtraction

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2 years ago

Step by step to this please

vladimir1956 [14]

Answer:

Step-by-step explanation:

1) Substitute the values of t, v, and w into the expression:

$(-2)^{2} + (1)(3)$

2) Simplify the terms:

$(-2)^{2} + (1)(3)\\=4 + 3\\= 7$

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2 years ago

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The Johnsons are expanding the family room. When the room is finished, it will be twice the original length and width. How many

a_sh-v [17]

You did not say or show the original length or width of the room.

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2 years ago

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Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie

Yakvenalex [24]

Volume of the pyramid:

$V=\dfrac{s^2h}3$

Perimeter of the cross-section:

$40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)$

$\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}$

Area of the cross-section:

$P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}$

$\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}$

First derivative test:

$\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3$

Then the height of the cross-section/pyramid is

$h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}$

The volume of the pyramid that maximizes the cross-sectional area $P$ is

$V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}$

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2 years ago

Which clock shows a time after<br> 3:15 but before 4:00

amid [387]

Answer:

there are no clocks to compare

Step-by-step explanation:

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2 years ago