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jolli1 [7]
3 years ago
10

David has four bags of apples and two bags of mangoes. The first four bags contain 6 apples each and the bags with mangoes conta

in 3 mangoes each. If David and his friends ate 2 apples from each bag and 2 mangoes from each bag, what is the total number of fruits left over?​
Mathematics
2 answers:
Neko [114]3 years ago
3 0

Answer:

tal vez sea el fotosíntesis pero no creo jaja

Step-by-step explanation:

pero mañana va?

katrin [286]3 years ago
3 0

Answer:

XDXDXDXDXDXDXD YO NO SE LA RESPUESTA :')

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konstantin123 [22]
Y=2(-1)^2-6(-1)+3
y=2+6+3
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Could you answers the question?
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3 years ago
Franco made a dozen muffins for his party. Upon taking them out of the oven,
Naddik [55]

Answer:

Option B.

Step-by-step explanation:

This question is incomplete; find the complete question with the attachment.

Franco made number of muffins = a dozen

A dozen muffins = 12 muffins

Number of muffins were burned = 2

Remaining muffins = 12 - 2 = 10

Franco served 7 of the remaining non-burned muffins,

Fraction of muffins served = \frac{7}{10}

Remaining muffins = 3

Fraction of remaining muffins = \frac{3}{10}

Fraction of remaining non-burned muffins we can get from,

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Option B is the correct equation.

7 0
4 years ago
A test has 50 questions. each right answer is worth 2 points; each wrong answer deducts 0.5 points; blank answers are not counte
mestny [16]

ANSWER: There are 2 blank answers

 

EXPLANATION

 

Let

The number of right answers be ‘r’

The number of wrong answers be ‘w’

The number of blank answers be ‘b’

 

r + w + b = 50

This means r + w ≤ 50

 

Then we know,

Right answers = 2 marks

Wrong answers = -0.5 mark

Blank Answers = 0 marks

 

2r – 0.5w = 88.5

2r = 88.5 + 0.5w                               … (Equation I)                   

 

Since the score as .5, we know that there is at least one wrong answer, and the number of wrong answers is an odd number.

 

Since the score is 88.5, and each right answer gives 2 marks

There are at more than 44 (i.e. 88/2) right answers

 

Since r + w ≤ 50, and possible values of w are odd numbers

If r = 45, Possible values of w are 1, 3, and 5

If r = 46, Possible values of w are 1, 3

If r = 47, Possible values of w are 1, 3

If r = 48, The only possible value of w is 1

If r = 49,The only possible value of w is 1

 

 

Since 2r = 88.5 + 0.5w  (Equation I)

We test for possible values:

 

If r = 45

2r = 88.5 + 0.5w  

2(45) = 88.5 + 0.5w  

90 = 88.5 + 0.5w

0.5w = 90 – 88.5

0.5w = 1.5

w = 3

 

So,

If there are 45 right answers

There are 3 wrong answers

r + w + b = 50

45 + 3 + b = 50

48 + b = 50

b = 50 – 48

b = 2

Then, there are 2 blank answers.

 

If r = 46

2r = 88.5 + 0.5w

2(46) = 88.5 + 0.5w

92 = 88.5 + 0.5w

0.5w = 92 – 88.5

0.5w = 3.5

w = 7

 

So,

If there are 46 right answers

There are 7 wrong answers

We know that r + w ≤ 50

46 + 7 = 53

So 46 and higher numbers are not possible solutions.

 

The only possible solution is:

There are 45 right answers

There are 3 wrong answers

<span>There are 2 blank answers</span>

6 0
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jonny [76]
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Let x = number of consoles to be bought
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The total cost would be equal to the sum of the price multiplied by the number of consoles, games and controllers bought. We write the algebraic expression as follows,

C = 299x + 59.99y + 29.99z
4 0
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