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lora16 [44]
3 years ago
15

U have 12 dogs all but 8 dogs died how many dogs are still alive

Mathematics
2 answers:
uysha [10]3 years ago
7 0
Hey you have to subtract the total dogs from the died dogs
which is 12 - 12 = 0
You have still no dogs alive.
mash [69]3 years ago
4 0
8 dogs are still alive because you take away 4 from 12 which equals 8
. 
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Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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The teacher paid $12 for 6 pounds of candy. Which statement is true about her unit<br> rate?
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Answer:

For every pound of candy, the teacher spent $2

Step-by-step explanation:

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