Answer:
9.72
Step-by-step explanation:
s1 = 10.6383 ; s2 = 5.21289
x1 = 147.583 ; x2 = 136.417
n1 = 12 ; n2 = 12
df1 = n1 - 1 = 12 - 1 = 11
df2 = n2 - 1 = 12 - 1 = 11
The test statistic :
(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]
Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)
Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926
Test statistic, T* :
(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))
11.166 / √(7.926 * (1/6)
11.166 / √1.321
11.166 / 1.1493476
T* = 9.7150766
Test statistic = 9.72
Answer:
any score that lies between 88.8 and 97.2 is within one std. dev. of the mean
Step-by-step explanation:
One std. dev. above the mean would be 93 + 4.2, or 97.2. One std. dev. below the mean would be 93 - 4.2, or 88.8.
So: any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.
Answer:
t=7/5
Step-by-step explanation:
If you subtract 3 from each side, you end up with -5t=-7. In order to keep t isolated, you would have to divide -5 on both sides. When you do this, you will end up with t= -7/-5. You also need to simplify that. When simplified you end up with t=7/5. Hope this helps!
Answer:
B
Step-by-step explanation:
Answer:
For this problem, simply substitute x in 
with the given x-values. The resulting coordinates should be (-3,2/27), (-2,2/9), (-1,2/3), (0,2), (1,6), (2,18), and (3,54). Now, you can plot the points, in order to get the exponential graph.
