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icang [17]
3 years ago
12

The kinetic energy of an object increases as its ____ increases.

Physics
1 answer:
slavikrds [6]3 years ago
3 0

Answer:

velocity

Explanation:

velocity is the answer

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A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
Kipish [7]

Answer:

its on wheels and they are supposed to make it eas

Explanation:

3 0
3 years ago
Which answer best explains why the contents of a warm can of carbonated drink might rush out of the can faster than the contents
Flura [38]

Answer:

its A

Explanation:

3 0
3 years ago
How much heat is required to raise 100 grams of water (c= 4.18) by 5 degrees Celsius?
Andrei [34K]

Answer:

Heat capacity, Q = 2090 Joules.

Explanation:

Given the following data;

Mass = 100 grams

Specific heat capacity = 4.18 J/g°C.

Temperature = 5°C

To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature of an object.

Substituting into the formula, we have;

Q = 100*4.18*5

Heat capacity, Q = 2090 Joules.

7 0
3 years ago
Once​ Kate's kite reaches a height of 50 ft ​(above her​ hands), it rises no higher but drifts due east in a wind blowing 7 ft d
Margaret [11]

Answer:

dz  = 7.136 (answer)

Explanation:

given height  for kate's kite   = 50 ft  (say y)

due to drift it move towards east =  dx = 7 ft  

string maximum length          = 107 ft ( say z)

we have to find change in z  

that is  dz

it will form a right angle triangle for x , y and z  where x is base y is height and z is hypotenuse

so we get according to Pythagoras Theorem

z^2 = x^2+y^2\\...............(i)

by derivative both side  consider y as constant

2zdz = 2xdx\\dz = {xdx }/z

from (i)  equation

x = \sqrt{z^2-y^2}

dz = \sqrt{z^2-y^2}dx/z

now put the value and find dz

dz = (\sqrt{120^2-50^2)}7/107\\  =((\sqrt{14400 -2500} )\times7)/107

after solving these  we get

dz  =\frac{109.08\times7}{107}  

dz  = 7.136 (answer)

7 0
3 years ago
Una persona cierra una puerta de 1 metro de ancho aplicando una fuerza de 40 [N], perpendicular a ella, a 90 [cm] de su eje de r
Damm [24]

Answer:

El módulo del torque aplicado es 36 Nm

Explanation:

En los movimientos rotatorios, la cantidad de fuerza aplicada no depende de la acción gravitacional sino del momento inercial, que es el equivalente angular de la inercia (masa) y representa la resistencia que un objeto ofrece al rotar alrededor de su eje. Cuando un cuerpo rígido rota alrededor de su eje debe considerarse , además de la masa, el radio de giro ya que estos dos factores determinan la resistencia del cuerpo a los cambios de movimiento rotatorio a través de un eje determinado.

De esta manera, se llama torque o momento de una fuerza a la capacidad de dicha fuerza para producir un giro o rotación alrededor de un punto.

En muchas ocasiones el punto de aplicación de la fuerza no coincide con el punto de aplicación en el cuerpo. En este caso la fuerza actúa sobre el objeto y su estructura a cierta distancia, mediante un  elemento que traslada esa acción de esta fuerza hasta el objeto. Entonces, el momento de una fuerza  es, matemáticamente,  igual al producto de la intensidad de la fuerza (módulo) por la distancia desde el punto de aplicación de la fuerza hasta el eje de giro:

M=F*d*sen θ

donde F es la fuerza en Newton (N), d la distancia en metros (m), θ el ángulo que forma la fuerza con el objeto al cual se le aplica la fuerza y M el momento, que se mide en Newton por metro (Nm).

En este caso:

  • F= 40 N
  • d= 90 cm= 0.9 m (siendo 100 cm= 1 m)
  • θ= 90° ya que la fuerza se aplica de forma perpendicular. Entonces sen θ= sen 90= 1

Reemplazando:

M=40 N*0.9 m* 1

Resolviendo:

M= 36 Nm

<u><em>El módulo del torque aplicado es 36 Nm</em></u>

3 0
3 years ago
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