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MatroZZZ [7]
4 years ago
9

ESSENTIAL QUESTION CHECK-ININHow can you use a number line to find the sum of -4 and 6

Mathematics
2 answers:
olga2289 [7]4 years ago
5 0
Yes the sum of -4 and 6 is 2

Stella [2.4K]4 years ago
3 0
Start from -4 and since its adding jump up 6 times up the number line and you get 2.
Hope it helps! Mark as brainliest!
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Bob bought a broken motor scooter, repaired it, and sold the scooter for $130. That was $50 less than 1.5 times what he paid for
FromTheMoon [43]

Answer: $120

Step-by-step explanation:

Assume the original price is x.

He sold the scooter for $130 and this was $50 less than 1.5 times what he paid for it.

Relevant formula is therefore:

1.5x - 50 = 130

1.5x = 130 + 50

x = 180/1.5

x = $120

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Jerry cycles a 36-mile loop every day for two weeks. What is the total
Semmy [17]
The answer is: 18 miles.

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Betsy can clean a/b of the house in an hour. How long will it take her to clean the whole house?
vagabundo [1.1K]

Answer:

b/a\ hours

Step-by-step explanation:

we know that

Betsy can clean a/b of the house in an hour

The whole house (100%) correspond to the number 1

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using proportion

Find out how long will it take her to clean the whole house

\frac{(a/b)}{1}=\frac{1}{x} \\ \\x=1/(a/b)\\ \\x=b/a\ hours

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3 years ago
PLZ PLZ PLZ ANSWER QUICK! WILL GIVE BRAINIEST! LOTS OF POINTS!
V125BC [204]

Answer:

b < 11  =  The board is shorter than 11 cm

b > 11  =  The box contain more than 11 blocks

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4 0
3 years ago
Read 2 more answers
For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

Now putting in eq(1) to get value of x

x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

4 0
3 years ago
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