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Vadim26 [7]
3 years ago
15

jen uses 8.2 of blue paint and white paint to paint her bedroom walls. 4/5ths of this amount is blue paint, and the rest is whit

e paint. how many pints of white paint did she use to paint her bedroom walls?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

The amount of white paint Jen used to paint the walls in her room is:

  • <u>1.64 pints.</u>

Step-by-step explanation:

To solve the exercise you only have to pay attention to the statement, in the section that says that 4/5 parts of the total painting is blue, therefore, if 1 is the total painting, you must do a subtraction:

  • 1 - 4/5 = 1/5

Since the remaining white paint is 1/5 of the total, you have two ways to solve the exercise: multiply the total paint (8.2 pints) by 1/5 or divide the number by 5, as shown below:

  • <u>Amount of white paint = 8.2 pints * (1/5) = 1.64 pints. </u>
  • <u>Amount of white paint = 8.2 pints / 5 = 1.64 pints. </u>

As you can see, the two methods provide a <u>value of 1.64 pints, which corresponds to 1/5 of the total paint and is the amount of white paint used</u>.

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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

3 0
3 years ago
During his trip, sara knits a bright, oranges scarf at the rate of 469 mm every hour. If her trip last 8 days and if sara sleeps
Tpy6a [65]

For this case, the first thing we must do is define variables.

We have then:

x: number of hours

y: Amount of scarf that Sara knits

We then have the following equation that models the problem:

y = 469 (x - 40)

The number of hours during the 8 days is given by:

x = 8 * (24-5)\\x = 152

Substituting the value of x in the ada equation we have:

y = 469 (152 - 40)\\y = 52528

Answer:

she will knitted by the end of the trip about 52528mm of scarf

3 0
3 years ago
Read 2 more answers
AB=<br> Round your answer to the nearest hundredth
Afina-wow [57]

Answer:

Step-by-step explanation:

2/sin25=AB/sin90

 AB=4.73

5 0
3 years ago
Please look at the picture because I can’t use the keyboard to explain
MariettaO [177]
There are 16 oz in a pound so 16*.75=12
6 0
3 years ago
Using the equation y = 3x – 5, what would the output be for an input of 2
Luba_88 [7]

Answer:

Step-by-step explanation:

y = 3x - 5.....input values are x and output values are y

so if ur input (x) is 2.....sub 2 in for x and find ur output (y)

y = 3x - 5

y = 3(2) - 5

y = 6 - 5

y = 1 <=== ur output value

3 0
4 years ago
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