For a radioactive isotope has an activity of 9.60 mCi. , the half-life of the isotope is mathematically given as
t0.5 = 23893 s
<h3>What is the half-life of the isotope?</h3>
Generally, the equation for the half-life is mathematically given as
t0.5=T*0.693
Where
A = A0 e^(-t/T)
t/T = lnA0/A
3.75 hours/T=ln 9.60/7.39
T = 34478.5 s
Therefore
t1/2 = TX0.693
t0.5 = 23893 s
In conclusion, the half life
t0.5 = 23893 s
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Answer:
The molality is 0.504 molal
Explanation:
Step 1: Data given
Mass of NaCl = 25.00 grams
Molar mass NaCl = 58.44 g/mol
Mass of water = 850.0grams
Step 2: Calculate moles NaCl
Moles NaCl = mass NaCl / molar mass NaCl
Moles NaCl = 25.0 grams / 58.44 g/mol
Moles NaCl = 0.428 moles
Step 3: Calculate molality
Molality = moles NaCl / mass H2O
Molality = 0.428 moles / 0.850 kg
Molality = 0.504 molal
The molality is 0.504 molal
Answer: The answer is the Pharynx I believe
Explanation: please correct me if I’m wrong