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Nadusha1986 [10]
2 years ago
12

Which way would CCI2F2 orient in an electric field?

Chemistry
1 answer:
ArbitrLikvidat [17]2 years ago
3 0

Answer:

See explanation

Explanation:

In looking at molecules to determine whether they are polar or not we have to look at two things basically;

i) presence of polar bonds

ii) geometry of the molecule

Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.

In an electric field, polar molecules orient themselves in such a way that  the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.

So the positive ends of CCI2F2  are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.

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45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Alex Ar [27]

45.6 mL of 0.0600 M of Ba(OH)_{2} is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : M_{1} V_{1} =  M_{2} V_{2}                 ...( 1 )

Where  M_{1}= concentration of Ba(OH)_{2}  =  0.0600 M ( given )

M_{2} = concentration of HCl = ? ( to be find )

 V_{1}= volume of Ba(OH)_{2}  = 25.0 mL  ( given )

V_{2} = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  M_{2}  × 45.6 mL

M_{2}  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

to learn about concentration here ,

brainly.com/question/10725862

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7 0
1 year ago
Fountain
iren2701 [21]

Answer:

4104 Coulombs

Explanation:

charge = time(sec) *current

25*60 =1500+20=1520

2.7A * 1520 sec =4104

4104 C

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2 years ago
Which statement regarding the gold foil experiment is FALSE? 1. The α particles were repelled by electrons. 2. It suggested that
Alenkinab [10]

Answer:

1. The α particles were repelled by electrons.

Explanation:

The gold foil experiment was performed by Rutherford and his research group in 1911 (at the beginning of the 20th century). In this experiment, α particles were bombed to gold foils, and films were placed surround it to collect the particles.

It was observed that most of the particles passed through of the foil undeflected, and for that, Rutherford stated that the atom was a "huge empty". Some particles were deflected, because they're attracted to the electrons at the electrosphere, and a small number of particles were complete deflected to the origin because they chocked with the small positive nuclei.

Thus, the experiment suggested the nuclear model of the atom, called the planetary model, that was improved after by Bohr and other scientists in the quantum model.

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mr Goodwill [35]
I only got 50 points (which is not 100). :-)

Look at the graph. At 80 °C, about 38 g of solute is able to dissolve, and that’s for ever 100 g of water. That means that for every 150 grams of water, 57 grams of solute can dissolve (38/2 = 19 + 38 = 57 g) at 80 °C. Since 57 g is greater than 55 g, all for he sodium chloride should dissolve in 150 g of water at 80 °C - you can put all of that into a “mathematical explanation”.
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What type of bonding is occuring in the compound below?
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