You are going to select 5 keyboards, from a set of 25 defective keyboards. When you select the first keyboard it may be have either electrical deffects or mechanical deffect, this is two possibilities. The same happens with the second, third, fourth and fifth selection. Then each selection has 2 different possibilities, and the number of possibilities are: 2*2*2*2*2 = 32.
But that is considering that the order matters. This is that it is different that the first has electrical deffects and the others have mechanical defects than the second has mechanical electrical deffects and the other has mechanical deffects.
If you the order is not relevant, then the only different outcomes are:
1) 5 with electrical deffects
2) 4 with electrical deffects and 1 with mechanical deffects
3) 3 with electrical deffects and 2 with mechanical deffects
4) 2 with electrical deffects and 3 with mechanical deffects
5) 1 with electrical deffects and 4 with mechanical deffects
5) 5 with mechanical deffects.
In this case the answer is 6 different ways.
Answer: 6
Since there were 72 fewer students tickets sold than adults tickets. the number of adult tickets that were sold is 278.
<h3>What is this algebra about?</h3>
Note that:
A total of 378 tickets were sold for the school play.
So:
A + S = 378
S = 2A
A + (2A) = 378
3A = 378
A = 126
If A is 126, then S is double of that, or 252.
126 + 252 = 278
Therefore, Since there were 72 fewer students tickets sold than adults tickets. the number of adult tickets that were sold is 278.
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