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3 years ago

Where does an electron in a metal get enough energy to escape from its atom as hypothesized in the photoelectric

2 answers:

8 0

When energy from incident photons is transferred to the electrons, an electron in a metal get enough energy to escape from its atom as hypothesized in the photoelectric effect.

Answer: Option D

<u>Explanation:</u>

At the point, when the light incident on a metal, electrons can be shot out from the outside of the metal in a wonder known as the photoelectric effect. This procedure is additionally frequently alluded to as photo emission, and the electrons that are shot out from the metal are called photo electrons. Regarding their conduct and their properties, photo electrons are the same as different electrons.

The prefix, photograph, basically discloses to us that the electrons have been shot out from a metal surface by incident light. In the light's wave model, Scientists predicted that expanding light amplitude increases the kinetic energy of radiated photo electrons while the increase in the intensity would increase in the estimated current.

Elina [12.6K]3 years ago

5 0

Answer:

D. Energy from incident photons is transferred to the electrons.

Explanation:

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El ancho de la uña de su dedo meñique se acerca a una unidad metrica comun ¿cual?

BartSMP [9]

Answer:

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3 years ago

What is the equivalent resistance between points A and C if R1=1430, R2=1350, R3=1100, R4=1350, and R5=1150.

Marianna [84]

R1 + R4 = 1430 + 1350 = 2780 = R14 series combination of R1 & R4

R2 + R5 = 1350 + 1150 = 2500 = R25

The circuit has been reduced to 3 resistors in parallel

R314 = 2780 * 1100 / (2780 + 1100) = 788 this is the resistance of the parallel combination of R14 and R3

R31425 = 2500 * 788 / (2500 + 788) = 599 which is the equivalent of the circuit - you can also use the formula for 3 resistors in parallel but this seems simpler

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3 years ago

a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/

LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

$0=V_{y}-g*t=v_{0}*sin(\alpha)-g*th\\$

we isolate th (needed to reach the maximum height hmax)

$th = \frac{v_{0}*sin(\alpha)}{g}$

The formula describing vertical distance is:

$y = Vy * t-g* t^{2} / 2$

So, given y = hmax and t = th, we can join those two equations together:

$hmax = Vy* th-g*th^{2}/2$

$hmax =Vo^{2}*sin(\alpha )^{2}/(2*g)$

if we launch a projectile from some initial height h all you need to do is add this initial elevation

$hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)$

$hmax =3+100^{2}*sin(45)^{2}/(2 * 32)=81 ft$

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3 years ago

Consider two wind turbines, each located in sites with the same wind speed, and each with the same efficiency. Turbine 1 has a r

Alex787 [66]

Answer:

shut up nerd

Exption:

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3 years ago

What is the net displacement of the particle between 0 seconds and 80 seconds?

Illusion [34]

After a thorough research, there exists the same question that has choices and the link of the graph (http://i37.servimg.com/u/f37/16/73/53/52/graph410.png)

<span>Choices:
A. 160 meters
B. 80 meters
C. 40 meters
D. 20 meters
E. 0 meters
</span>
The correct answer is letter E. 0 meters.

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3 years ago