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3 years ago

Where does an electron in a metal get enough energy to escape from its atom as hypothesized in the photoelectric

2 answers:

8 0

When energy from incident photons is transferred to the electrons, an electron in a metal get enough energy to escape from its atom as hypothesized in the photoelectric effect.

Answer: Option D

<u>Explanation:</u>

At the point, when the light incident on a metal, electrons can be shot out from the outside of the metal in a wonder known as the photoelectric effect. This procedure is additionally frequently alluded to as photo emission, and the electrons that are shot out from the metal are called photo electrons. Regarding their conduct and their properties, photo electrons are the same as different electrons.

The prefix, photograph, basically discloses to us that the electrons have been shot out from a metal surface by incident light. In the light's wave model, Scientists predicted that expanding light amplitude increases the kinetic energy of radiated photo electrons while the increase in the intensity would increase in the estimated current.

Elina [12.6K]3 years ago

5 0

Answer:

D. Energy from incident photons is transferred to the electrons.

Explanation:

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nexus9112 [7]

Because they are different they all show different traits.

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3 years ago

If you can throw a stone straight up to height h, what’s the maximum horizontal distance you could throw it over level ground?

Mariana [72]

To answer this question, first we take note that the maximum height that can be reached by an object thrown straight up at a certain speed is calculated through the equation,
Hmax = v²sin²θ/2g
where v is the velocity, θ is the angle (in this case, 90°) and g is the gravitational constant. Since all are known except for v, we can then solve for v whichi s the initial velocity of the projectile.

Once we have the value of v, we multiply this by the total time traveled by the projectile to solve for the value of the range (that is the total horizontal distance).

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3 years ago

Read 2 more answers

PLZ HELP!!!!

FrozenT [24]

I would think the answer is c.

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3 years ago

Read 2 more answers

for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th

mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

I is moment of inertia of the solid cylinder
α is angular acceleration of the cylinder
T is tension in the string
r is length of the string

α = Tr/I

$\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}$

where;

a is the downward acceleration of the solid cylinder
R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

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2 years ago

At what speed is a particle's kinetic energy twice its rest energy?

bezimeni [28]

The total energy of a particle is its rest energy plus the kinetic energy. Its formula is: Et= m^2/sqrt((1-v^2)/c^2))
The rest energy is equal to the product of mass and the square of light velocity: Er=mc^2.
When the kinetics energy is twice its rest energy this holds:
Et=Er
m^2/sqrt((1-v^2)/c^2))=<span>mc^2.
</span><span>sqrt((1-v^2)/c^2))=m/c^2
</span>=> v=sqrt(3/2)c

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3 years ago