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alexgriva [62]
3 years ago
5

A waist-to-hip ratio of 1.0 is considered healthy. True False

Physics
2 answers:
rjkz [21]3 years ago
8 0

Answer: False

Explanation:

The waist to hip ratio can be define as the dimensionless ration which measures the circumference of waist to hip. It is obtain by dividing the circumference of the waist to that of the circumference of hip. The waist to hip ratio more than 1 can be considered as risk in development of heart disease. A healthy women is expected to have a waist-hip ratio under .80 and for healthy males it should be equal to and less than .90.

On the basis of the above description, the statement, A waist-to-hip ratio of 1.0 is considered healthy is false.

laila [671]3 years ago
7 0
false a waist to hip ratio that is healthy would be .80 or less is considered healthy for most individuals hope this helps
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A point charge q = -0.45 nC is fixed at the origin. Where must an electron be placed in order for the electric force acting on i
ziro4ka [17]

Answer:

Electron must be placed at a distance of 2.69 ×10^5 m in the direction of positive y-axis.

Explanation:

Charge on electron = e = -1.6 × 10^-19 C

Mass of electron = m = 9.1 × 10^-31 kg

Charge at origin = q = -0.45 nC  

According to given condition in the question:

                       Fe = Fg

                   kq1q2/r^2 = mg  

(9 × 10^9)( -1.6 × 10^-19)( -0.45n)/r^2 = (9.1 × 10^-31)(9.8)

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                    r = 2.69 ×10^5 m      in the positive y-axis direction  

3 0
3 years ago
Suppose you are in an elevator that is moving upward with a constant velocity. A scale inside the elevator shows your weight to
Ulleksa [173]

Answer:

a) Less than 600 N

b) 600 N

c) Less than 600 N

Explanation:

The value registered by the scale, measures the normal force on the object placed on the scale.

The person on the scale, is acted by two external forces, gravity (which we call weight, and always go downward) and the normal force, an upward force in this case.

The difference between both forces, according Newton’s 2nd law, must be equal to the product of the mass of the object, times the acceleration.

If the elevator moves upward to a constant speed, and then slows down, this means that there exists a net force on the person, producing a acceleration directed downwards on him.

If we take the direction of the acceleration (downward) to be positive, this means that the difference between gravity force and normal force must be positive.

As mg = 600 N (equal to normal force when no net force is present), the normal force in this case must be less than 600 N.

b) If the elevator is stopped, the effect is the same like it were moving at constant speed, so in this case the normal force remains the same: 600 N

c) Assuming that it starts from rest, if it accelerates going downward, and if we take as positive the downward direction, in order to satisfy Newton’s 2nd Law, normal force must be less than 600N so the difference between gravity and normal force remain positive.

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4 years ago
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Explanation:

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Espero eso ayude. Marque como más inteligente.

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ludmilkaskok [199]
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