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2 years ago

A plane starting at rest at one end of a runway undergoes a uniform acceleration of 4.8 m/s

Physics

1 answer:

yKpoI14uk [10]2 years ago

8 0

initial velocity=0m/s=u
Acceleration=a=4.8m/s^2
Time=t=15s

Final velocity be v

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+4.8(15)$

$\\ \sf\longmapsto v=72m/s$

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<u>Motion in The Plane</u>

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$\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2$

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