Answer:
you are supposed to divide it
Step-by-step explanation:
41divided by 85=
Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
The two triangles are isosceles.
Both triangles have the equals sides equal to 6
Both ∠ 1 and the ∠2 are the opposite angles to the different side of their respective triangles.
The opposite side to ∠ 1 is shorter than the opposite side to ∠ 2, which implies that ∠1 is less than ∠2.
Then the inequality that relates those angles is
∠1 < ∠2
The total area of the shape is 32
the value of a is 2 bc by looking at the graph a normal parabola of x^2 would bc followinf the 1-3-5 rule but this does not
from the vertex it goes over 1 and up 2