What you do is you rearrange and simplify both equations to have them in terms of y, and then graph them. If it asked for a solution, their point of intersection would be the solution.
Answer:
C
Step-by-step explanation:
To solve, use inverse operations:
![(x+6)^2=49\\\sqrt{(x+6)^2} =\sqrt{49} \\x+6=+/-7](https://tex.z-dn.net/?f=%28x%2B6%29%5E2%3D49%5C%5C%5Csqrt%7B%28x%2B6%29%5E2%7D%20%3D%5Csqrt%7B49%7D%20%5C%5Cx%2B6%3D%2B%2F-7)
Now we solve for both +/- 7.
x+6=7
x=1
x+6=-7
x=-13
Store B, since they are two for 4.20$ while Store A has only ONE for 3.00$ meaning let’s say we’re gonna buy two packs it would be 4.20$ for Store B and 6.00$ for Store A
If the area is 10 square meters than double that is area of a rectangle with height = 5m and base of 4m because height • base should produce 20m^2.
Hope this helps.
Answer:
x ≈ 5.89
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Exponential to Logarithmic:
![\displaystyle b^m=x \rightarrow log_bx=m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b%5Em%3Dx%20%5Crightarrow%20log_bx%3Dm)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
0.77 = log(x)
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Raise both sides to the 10th power:
![\displaysytle 10^{0.77} = 10^{logx}](https://tex.z-dn.net/?f=%5Cdisplaysytle%2010%5E%7B0.77%7D%20%3D%2010%5E%7Blogx%7D)
- Simplify:
![\displaysytle x = 10^{0.77}](https://tex.z-dn.net/?f=%5Cdisplaysytle%20x%20%3D%2010%5E%7B0.77%7D)
- Evaluate:
![\displaysytle x = 5.88844](https://tex.z-dn.net/?f=%5Cdisplaysytle%20x%20%3D%205.88844)