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d1i1m1o1n [39]
3 years ago
13

A 15% discount saves you $5 off the price of an electronic game. How much do you save off the regular price if the discount is w

as raised to 45%? Explain your reasoning.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

The 45% off discount saves an additional $10 compared to the 15% discount for a total of $15 off regular price.

Step-by-step explanation:

We can find the original price of the game through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio  of $ to $. Since 15% of 100% is the same ratio as $5 to the unknown original $ price, I write:

\frac{15}{100} =\frac{5}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

15y=100(5)\\15y=500

I now solve for y by dividing by 15.

\frac{15y}{15} =\frac{500}{15} \\y= 33.33333....

The original price was $33.34.

Now, we can find the amount if 45% off and then then compare the two discounts. To find the percent off I can multiply by 0.45(33.34)=15. The 45% off discount saves an additional $10 compared to the 15% discount.

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Alice and Bob are playing a game. Alice starts first. On Alice's turn, she flips a coin. If she gets a heads, she wins. If not,
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Answer:

The probability that Alice wins the game=\frac{1}{2}

Step-by-step explanation:

We are given that Alice and Bob are playing a game .

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8 0
3 years ago
1.    An AP has a common difference of 3.  Given that the nth term is 32, and the sum of the first n terms is 185, calculate the
netineya [11]

Answer:

The value of n is 10

Step-by-step explanation:

The formula of the nth term of the arithmetic progression is a_{n} = a + (n - 1)d

  • a is the first term
  • d is the common difference between each 2 consecutive terms
  • n is the position of the term

The formula of the sum of nth terms is S_{n} = \frac{n}{2} [2a + (n - 1)d]

∵ An AP has a common difference of 3

∴ d = 3

∵ The nth term is 32

∴ a_{n} = 32

→ Substitute them in the 1st rule above

∵ 32 = a + (n - 1)3

∴ 32 = a + 3(n) - 3(1)

∴ 32 = a + 3n - 3

→ Add 3 to both sides

∴ 35 = a + 3n

→ Switch the two sides

∴ a + 3n = 35

→ Subtract 3n from both sides

∴ a = 35 - 3n ⇒ (1)

∵ The sum of the first n terms is 185

∴ S_{n} = 185

→ Substitute the value of S_{n} and d in the 2nd rule above

∵ 185 = \frac{n}{2} [ 2a + (n - 1)3]

∴ 185 = \frac{n}{2} [2a + 3(n) - 3(1)]

∴ 185 = \frac{n}{2} [2a + 3n - 3]

→ Multiply both sides by 2

∴ 370 = n(2a + 3n - 3)

∴ 370 = 2an + 3n² - 3n

→ Substitute a by equation (1)

∴ 370 = 2n(35 - 3n) + 3n² - 3n

∴ 370 = 70n - 6n²+ 3n² - 3n

→ Add the like terms in the right side

∵ 370 = -3n² + 67n

→ Add 3n² to both sides

∴ 3n² + 370 = 67n

→ Subtract 67 from both sides

∴ 3n² - 67n + 370 = 0

→ Use your calculator to find n

∴ n = 10 and n = 37/3

∵ n must be a positive integer ⇒ 37/3 neglecting

∴ n = 10

∴ The value of n is 10

4 0
3 years ago
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