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3 years ago

Please help me and give me a detailed answer thank u!

Mathematics

2 answers:

crimeas [40]3 years ago

7 0

Answer:

18 inches

Step-by-step explanation:

If sue wants to enlarge the photo so the length is 30 inches, since the photo is orginally 5 inches long, figure out 5 times what equals 30

Since 5 times 6 equals 30, multiply the width by 6 too

3/5 = 18/30

ddd [48]3 years ago

6 0

3/5 = 18/30 is the answer

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How did you compute sums of dollar amounts that were not whole numbers? For example, how did you compute the sum of$5.89 and$1.4

nignag [31]

Answer:

$7.34

Step-by-step explanation:

To compute sum of dollars that are not whole numbers. Using the sum of$5.89 and$1.45 as an illustration :

$5.89 + $1.45

Taking the whole numbers first:

$5 + $1 = $6

Take the sum of the decimals :

$0.89 + $0.45 = $1.34

Sum initial whole + whole of sum of decimal

$6 + $1 = $7

Remaining decimal : $1.34 - $1 = $0.34

$7 + $0.34 = $7.34

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3 years ago

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vlada-n [284]

Answer:

7. B 8. C 9. C

Step-by-step explanation:

7. y is greater than because the area above the line is shaded and since the line is dashed there it's not greater than or equal to.

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8 0

2 years ago

The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:

blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}$

$=\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182$

Compute the standard deviation as follows:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

$=\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899$

Thus, the standard deviation of the age distribution is 6.2899 years.

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2 years ago

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

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3 years ago

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