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GarryVolchara [31]
4 years ago
9

Hurry hurry answer these so I don't get grounded!

Chemistry
1 answer:
TEA [102]4 years ago
6 0
1. Tributary
2. Erosion
3. Where a river turns
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I have no idea how to do this, any help would be appreciated
aksik [14]
Proton number = the atomic number (which is the smaller number
neutron number = the mass number (the bigger number) - the atomic number
number of electrons = the atomic number - the charge (it depends on the element but group 1 is +1 group 2 is +2 group 3 is +3 group five is -3 group six is -2 group seven is -1


i would solve the whole thing but its unclear hope this helps tho
6 0
3 years ago
What is the position of the element ammonia in periodic table?
Rashid [163]
Ammonia isn't an element, it's a compound made by mixing the elements Nitrogen and Hydrogen in the Haber process. Therefore, it isn't on the periodic table
8 0
3 years ago
Read 2 more answers
Seaborg co-discovered 10 new elements and they were moved out of the main group to the
Alja [10]
Other group because they weren’t in the right group
5 0
3 years ago
You need to measure the brightness of a light bulb using the metric system. In which unit do you express your measurement?
kherson [118]
Candela is the correct answer. In measuring the brightness or luminosity of the bulb and you want to use the metric system, candela is the unit to be used. You are correct that candela is the unit of light intensity. The term candela is the Latin for candle which signifies light.<span> </span>
7 0
4 years ago
1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL
nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c  =   \frac{n}{v}

⇒  n = c ⋅  V

n_{HCL} =  0.250 M  ⋅  6.00 L  = 1.5 moles HCl

Now all you have to do is figure out what volume of   6.0 M  stock solution will contain  1.5  moles of hydrochloric acid

c = \frac{n}{v}

V = \frac{n}{c}

V_{Stock} = \frac{1.5 moles}{6.0 \frac{moles}{L} }   = 0.25 L

Expressed in milliliters, the answer will be

V_{Stock} = 250ML →  rounded to two sig figs

7 0
3 years ago
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