<u>Answer:</u> The rate law expression is and value of 'k' is
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to nitrogen monoxide
b = order with respect to oxygen
- <u>Expression for rate law for first observation:</u>
....(1)
- <u>Expression for rate law for second observation:</u>
....(2)
- <u>Expression for rate law for third observation:</u>
....(3)
Dividing 1 from 2, we get:
Dividing 1 from 3, we get:
Thus, the rate law becomes:
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
Hence, the rate law expression is and value of 'k' is
1. False
2. ?
3. same as 2
4. True
5. False
6. False
7. ?
8. ?
9. True
10. False
Answer:
a. Second order
b. First order
c. zero order
Explanation:
a. For a second order reaction,
As half life is inversely proportional to initial concentration, therefore, increase in intital concentration will decrease half life of the reaction.
b. First order reaction,
for first order reaction:
y = C + mx
Therefore, plot between ln A and t is a straight line.
c. For a zero order reaction,
Half life is proportional to initial concentration, therefore, increase in initial concentration will increase half life of the reaction.