<h2>Answer:</h2>
He is right that the energy of vaporization of 47 g of water s 106222 j.
<h3>Explanation:</h3>
Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.
In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.
It means for vaporizing 18 g, 40.65 kJ energy is needed.
So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ
Hence the student is right about the energy of vaporization of 47 g of water.
(2) three fewer valence electrons is your answer.
The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
3.80 x 103 J
The relationship between volume and temperature of a gas, when pressure and moles of a gas are held constant, is: V*T = k.
FALSE
The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n = k. We could say then, that:
If the moles of gas are tripled, the volume must also triple.
If the temperature and volume of a gas are held constant, an increase in pressure would most likely be caused by an increase in the number of moles of gas.
TRUE
If the vapor pressure of a liquid is less than the atmospheric pressure, the liquid will not boil.
TRUE
35 - AB
36 - BD
33 - true
34 - False
20 - 6
21 - orthohombic
