Answer:
D.
Explanation:
The data set has no correlation and cannot be accurately represented with a linear equation.
there seems to be no relation between the numbers
if you know the x value, you can't really guess what its y value is (no correlation)
First we must understand the balanced chemical equation:
Pb(NO3)2 + K2CrO4 ==> PbCr04 + 2KNO3
This shows us that two moles of potassium nitrate are formed from 1 mole of lead nitrate or potassium chromate solution. The next step is to find out how many moles of each reactant there are. Note the word Molar is a concentration that simply means moles per liter.
2.25L of 1.5M lead nitrate = 2.25x1.5 = 3.375 moles of lead nitrate
1.15L of 2.75M potassium chromate = 1.15x2.75 = 3.1625 moles
The important part here is to see that the number of moles of the reactants are different. We know the number of moles of products will be dependent on the number of moles of reactants, and in this case there is less potassium chromate than there is lead nitrate, so this is the limiting factor as there is a one to one relationship with both reactants. Therefore, the number of moles of potassium nitrate produced is 2 x number of moles of potassium chromate. i.e. 6.325 moles of potassium nitrate is liberated.
To work out the number of grams, we must find the molar mass (the mass of one mole) of KNO3, which is the sum of the molar mass of each of its component atoms that make up the molecule. I've looked this up as 101.1 grams per mole.
Now we simply times the molar mass by the number of moles to yield the final grams liberated: 6.325 moles x 101.1 grams/mole = 639.4 grams of potassium nitrate is liberated from this reaction.
Answer:
it represents the mating between males and females is shown by a horizontal line between their respective symbols.
Explanation:
It shows up in your stool. Specifically the undigested food includes material that cannot be absorbed by the vili found in the small intestine. Thereafter the material moves to the large intestine, goes through the bowel tract, turns into feces and exits the GI tract via the rectal cavity
