Answer:
4:10.
Step-by-step explanation:
4:10 would be one.
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
Answer:
No, images are not same as their dimensions are different although two sides in each of the two triangles are equal.
Step-by-step explanation:
Given: images of two isosceles triangles.
To check: if images are the same
Solution:
A triangle is a polygon made up of three sides.
An isosceles triangle is a triangle in which two sides are equal. Also, in an isosceles triangle, angles opposite to equal sides are equal.
The given images of two isosceles triangles A and B are not the same as their dimensions are different although two sides in each of the two triangles are equal.
That condition is true if P(A) and P(B) are independent of one another. For example, if I was pulling marbles out of a bag, if I am replacing the marbles back after I pull one out, then P(A or B) = P(a)+P(B).
