Answer:
no.
Step-by-step explanation:
since 2 of the sides are much longer than the shorter sides, diagonals of a rectangle will not intersect at a right angle (perpendicular) whereas a square, with all sides equal, would. This is because the distance from the center to each of the corners is the same for each corner.
From the diagram above,
XZ = 10 in and OX = 10 in
we are to find length of OY
XZ is a chord and line OY divides the chord into equal length
Hence, ZY=YX= 5 in
Now we solve the traingle OXY
To find OY we solve using pythagoras theorem

applying values from the triangle above
![\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20OX%5E2%3DXY%5E2%2BOY%5E2%20%5C%5C%2010%5E2%3D5%5E2%2BOY%5E2%20%5C%5C%20100%3D25%2BOY%5E2%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%20100%20-25%7D%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%2075%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B75%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B25%5Ctext%7B%20%7D%5Ctimes%5Ctext%7B%203%7D%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%205%7D%5Csqrt%5B%5D%7B3%5Ctext%7B%20%7D%7Din%20%5Cend%7Bgathered%7D)
Therefore,
Length of OY =
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:

And for this case we can use the Sylow theorems, given by:
Let G a group of order
where p is a prime number, with
and p not divide m then:
1) 
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168
Correct option is C. There are 20 ordered pairs.
Given that ordered pairs (x,y)
such that x is even integer where 4≤x≤10 and y is an integer.
where 4<y<10.
Then even integer 4≤x≤10 are four i:e
4,6,8,10
And integer 4<y<10 are five i:e
5,6,7,8,9
Then ordered pair are = 4×5=20
<h3>What are ordered pairs?</h3>
An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses. It helps to locate a point on the Cartesian plane for better visual comprehension. The numeric values in an ordered pair can be integers or fractions.
To learn more about ordered pairs from given link
brainly.com/question/1528681
#SPJ4
Answer:
The top of the ladder is 6.3 feet high from the ground.
Step-by-step explanation:
The given question can be expressed by the three sides of a right angled triangle. Let the height of the top of the ladder from the ground be represented by h.
Thus, applying the Pythagoras theorem to determine h, we have;
=
+ 
=
+ 
121 =
+ 81
= 121 - 81
= 40
h = 
= 6.325
h = 6.325 feet
The top of the ladder is 6.3 feet high from the ground.