3 = –(–y + 6) a. –9 b. –3 c. 3 d. 9
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Answer:
1. The shape of the histogram created with MS Excel is approximately bell shaped and approximately evenly spread about the central (largest counts) values
The shape of the box plot created with MS Excel is approximately evenly distributed
2. The appropriate measure of central tendency for a bell shaped histogram is the mean and median, due to the approximately equal distribution about the highest frequency class
3. Part A
The 15 numbers between 1 and 20 generated by a random generator are;
1, 8, 8, 15, 4, 18, 11, 6, 17, 1, 18, 15, 10, 12, 11
The measure of center is the mean = (1+8+8+15+4+18+11+6+17+1+18+15+10+12+11)/15 = 155/15 = 31/3
The measure of spread used is the variance, s² = 32.38
= 453.333
n = 15
s² = 453./(15 - 1) = 32.38
Part B
The measure of central tendency are the mean and the median because the size of the data (n = 15), is 75% of the population (N = 20) nd therefore the data is approximately normal and can be represented by the mean and the standard deviation
Step-by-step explanation:
