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4 years ago

Which variable is directly proportional to frequency?

Physics

2 answers:

Karo-lina-s [1.5K]4 years ago

5 0

Answer: The frequency is directly proportional to energy of the wave.

Explanation:

Frequency is defined as the number of waves that passes a given point per second. It is expressed in Hertz. It is denoted by the symbol $\nu$

The equation that links energy of the particle and frequency of the particle is given by Planck's equation, which is:

$E=h\nu$

where,

E = energy of the particle

h = Planck's constant

$\nu$ = frequency of the particle

Hence, the frequency is directly proportional to energy of the wave.

zhuklara [117]4 years ago

4 0

For this case we have by definition:

v = λf

We observe that we have a linear relationship, where λ is the constant of proportionality.

We have then:

v: speed of propagation of the wave
λ: wavelength
f: frequency

Answer:

The variable that is directly proportional to the frequency is λ, the wavelength.

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Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

For aluminium:

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

For copper:

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

Aluminium wire:

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

Copper wire:

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

3 years ago

What is the maximum walking speed of an adult man whose legs are each 1.2 m long?

lubasha [3.4K]

The average walking speed for an adult would be around 6 m/s, and average leght of adult human legs is around 1m so the best answer of the given answers would be 7.9 m/s

4 0

3 years ago

If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens

amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

Centrifugal force is mathematically related as:

$F=m.r.\omega^2$