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RUDIKE [14]
2 years ago
5

a 4kg box is resting on top of a shelf that is 2m high, what is the boxs gravitational potential relative to the floor​

Physics
2 answers:
Aloiza [94]2 years ago
6 0

Answer:

80 J

Explanation:

PE = mgh

PE = (4 kg)(9.8 m/s^2)(2 m)

PE = 78.4 J and with sig figs, it would be 80 J

Svet_ta [14]2 years ago
4 0
The answer is most definitely 80j
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A rigid rectangular loop, which measures 0.30 m by 0.40 m, carries a current of 5.5 A, as shown in the figure. A uniform externa
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Answer:

The magnitude will be "(1.097 \ N/m)\hat{j}". The further explanation is given below.

Explanation:

Trying to determine what is usual for a rectangular loop plane,

⇒  \hat{n}=(Cos35^{\circ})(-\hat{i})+(Sin35^{\circ})(\hat{k})

Magnetic moment is given as:

μ = IA\hat{n}

On putting the values in the above formula, we get

μ = (5.5A)[(0.3m)(0.4m)][(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(-\hat{k})]

  = 0.66 Am^2[(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(\hat{k})]

Now the external vector-shaped torque seems to be:

Magnitude,

\sigma=\hat{\mu}\times\hat{\beta}

On putting the values in the above formula, we get

⇒ \sigma=[(0.06Am^2)(Cos35^{\circ}(-\hat{i})+Sin35^{\circ}(-\hat{k})]\times (2.9T)(-\hat{i})

⇒    = (0.66)(2.9)Cos35^{\circ}(\hat{i}\times \hat{i})+(0.66)(2.9)Sin35^{\circ}(\hat{k}\times \hat{k})

⇒    = 0+(1.97 \ N/m)\hat{j}

⇒    =(1.097 \ N/m)\hat{j}

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Some of the storage tanks that are exempt from the federal regulations on USTs are;

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