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Nata [24]
3 years ago
9

In a demonstration, a 4.00 cm2 square coil with 10 000 turns enters a larger square region with a uniform 1.50 T magnetic field

at a speed of 100 m/s. The plane of the coil is perpendicular to the field lines. If the breakdown voltage of air is 4 000 V/cm on that day, the largest gap you can have between the two wires connected to the ends of the coil and still get a spark is:
Physics
1 answer:
Kay [80]3 years ago
6 0

Explanation:

It is given that,

Area of square coil, A=4\ cm^2=0.0004\ m^2

Side of the square, L = 0.02 m

Number of turns, N = 10000

Uniform magnetic field, B = 1.5 T

Speed, v = 100 m/s

An emf is induced in the coil which is given by :

E=NBLv

E=10000\times 1.5\times 0.02\times 100

E = 30000 V

Breakdown voltage of air, V=4000\ V/cm=400000\ V/m

Let d is the gap between the two wires connected to the ends of the coil and still get a spark. So,

Electric field, E'=\dfrac{V}{d}

\dfrac{30000}{d}=400000

d = 0.075 m

Hence, this is the required solution.

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It is called a table
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A 6 cm object is 8 cm from a convex lens that has a focal length of 5 cm. The image is 4 cm from the Lens . What's is the height
Llana [10]
H=6cm(height of the object)
D=8cm(distance of the object from the lens)
d=4cm(distance of the image from the lens)
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h=?(height of the image)
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M = H/D = h/d
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h=H×d/D
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The height of the image is 3cm.
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3 years ago
When a spaceship is traveling at 99% of the speed of light (Lorentz factor = 7), an astronomer on board the ship will find thata
Natali5045456 [20]

Answer:

e) True. Measure the own values, so everything seems normal

Explanation:

In the case of special relativity, it is explicitly stated that the speed of light is constant and equal to c for all inertial observers. For this reason the measures of time and length are no longer the same for observers moving with respect to each other.

We call the time and the proper length the magnitude measured for an observer who does not move with respect to the measurement system.

In this case the astronomer is on the ship, for him he does not feel the movement of it, they are at rest with respect to each other. Therefore, their measurements are the so-called ones, this means that their values ​​do not change since the two go at the same speed.

In examining the final statements we have

A) False. The mass measures not

B) False. Measure own length

C) False

D) false

e) True. Measure the own values, so everything seems normal

6 0
3 years ago
The space shuttle undergoes an acceleration of 53.9 m/s. How fast is it traveling at the end of 55.2 s?
const2013 [10]

It is traveling at the end of 55.2 s in the speed of 2975,28m/s

acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. In this instance, you requested the speed and provided the time, acceleration, and speed. Speed is calculated as follows: speed = distance * time. Knowing the units for distance and time is necessary to calculate the units for speed. Since acceleration is equal to time, multiplying the two numbers equals speed. The formula would be:

Acceleration x Time Equals Velocity

Velocity: 53.9 m/s2 x 55.2

           = 2975,28 m/s

Learn more about speed here-

brainly.com/question/28224010

#SPJ9

3 0
1 year ago
A 125kg automobile with a tangential speed of 48.0 km/h follows a circular road that has a radius of 35.0m how large is the cent
Gnoma [55]

Answer:

Centripetal force = 634.6  newton

Explanation:

Given that,

Weight of the automobile, M = 125 Kg

The tangential speed of the automobile, V = 48 Km/h

                                                             V = 13.33 m/s

The radius of the circular road, R = 35 m

The centripetal force is given by the relation

                        Fc = MV²/R

Where  M - the mass of the body

             V - velocity of the body

             R - Radius of its trajectory

Substituting in the above equation

                       Fc = 125 Kg x 13.33² m²/s²    /    35 m

                            = 22211.11 / 35  newton

                            = 634.6  newton

Hence, the centripetal force acting on the automobile is 634.6 N

7 0
3 years ago
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