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xenn [34]
3 years ago
12

21. The parent function of the following graph is f(x) = 2^x. What is the equation of the following graph?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

5

Step-by-step explanation:

vaieri [72.5K]3 years ago
7 0

Plug x = 0 into f(x) to get

f(x) = 2^x

f(0) = 2^0

f(0) = 1

The y intercept (0,1) is on the graph of f(x).

The y intercept for the red curve shown is (0,3). It has been moved up two units compared to (0,1)

Therefore, g(x) = f(x)+2 where g(x) represents the red curve.

g(x) = f(x) + 2

g(x) = 2^x + 2 is the answer

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Answer:

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Step-by-step explanation:

For m, I look for the greatest power of m that is in all of the expressions. Since the first has m^2, the second has m, and the third has m^4, the greatest power of m that is in all expressions is m.

For the number, I look for the greatest factor of 8, 4, and 10. A trick would be to look at the smallest number since the greatest common factor can only be less than or equal to the smallest number. So looking at 4, the factors are 1,2,4. 4 is not a common factor since it does not divide into 10, but 2 is so 2 is the greatest common numerical factor.

Combine 2 and m to get 2m.

4 0
4 years ago
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3 years ago
Use the appropriate normal distribution to approximate the resulting binomial distributions. A convenience store owner claims th
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Answer:

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Step-by-step explanation:

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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
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Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
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