Answer:
Equation : x + 1 + 3x = 7
Miles Lissette biked : 3/2 miles
Step-by-step explanation:
<em>Step 1: Determine the total number of miles biked.</em>
From my understanding. 7 miles is the total number of miles biked by both.
<em>Step 2: Assume the values</em>
Miles Lissette biked = x
Miles Shane biked = 1 + 3x
<em>Step 3: Add miles biked by Lissette and Shane which will be equal to total miles. </em>
Equation for miles Lissette biked: x + 1 + 3x = 7
4x + 1 = 7
x = 6/4
<em>Step 4: Simplify</em>
x = 6/4
x = 3/2
Therefore, the equation for miles Lissette biked is x + 1 + 3x = 7 and Lissete biked for 3/2 miles.
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Answer:
i think its b
Step-by-step explanation:
Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
Step-by-step explanation:
I think it is D but I am not sure
Unsure of what you are asking!
But if the issue here is how to define a line segment, write what you do know and then reconsider "undefined terms."
A line segment is a straight line that connects a given starting point and given ending point.
If you consider a circle of radius 3 units, the radius can be thought of as the line segment connecting the center of the circle to any point on the circumference of the circle.
If the center of a given circle is at C(0,0) and a point on the circumference is given by R(3sqrt(2),3sqrt(2)), then AC is the line segment joining these two points. This line segment has length 3 and is in the first quadrant, with coordinates x=3sqrt(2) and y=3sqrt(2) describing the end point of the segment.
