45 dimes and 93 nickels were in bank
<em><u>Solution:</u></em>
Let "n" be the number of nickels
Let "d" be the number of dimes
We know that,
value of 1 nickel = $ 0.05
value of 1 dime = $ 0.10
<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>
Number of nickels = 3 + 2(number of dimes)
n = 3 + 2d ---- eqn 1
<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>
number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15
0.05n + 0.10d = 9.15 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 1 in eqn 2
0.05(3 + 2d) + 0.10d = 9.15
0.15 + 0.1d + 0.10d = 9.15
0.2d = 9
<h3>d = 45</h3>
From eqn 1
n = 3 + 2(45)
n = 3 + 90 = 93
<h3>n = 93</h3>
Thus 45 dimes and 93 nickels were in bank
Answer:
◻DELS ~ ◻KARP is incorrect
Step-by-step explanation:
All of the similarity statements have corresponding letters in the same order except ...
◻DELS ~ ◻KARP . . . . (incorrect)
_____
The correct version would be ...
◻DELS ~ ◻KRAP
Answer:
2/6 - simplified fraction=1/3
Step-by-step explanation:
Answer:
29
Step-by-step explanation:
Answer:
50
Step-by-step explanation:
For this question you would follow the BIDMAS rule - (Brackets, Indices, Division, Multiplication, Addition, Subtraction.)
The first thing in this question you need to solve it (9 + 8)
we do this because, when we follow BIDMAS, the first rule is brackets
so, 9 + 8 = 17
The second step is to multiply, as this rule is second,
so, 17 x 2 = 34
Our final step is to solve the last bit, which is 6 x 14
and we know that 6 x 14 = 84
So now that we have 84 and 34, we need to subtract the two numbers as shown,
84 - 34 = 50
And this is how you get the answer 50
i hope this has helped you, please comment if you did not understand it and i will explain it in another way : )
