This is the concept of algebra; given that the height of the house at time t is given by:
h(t)=<span> 400 − 39t − 157e−t/4
the velocity of the house is given by:
dh/dt
velocity of our object is:
dh/dt=-39+1/4*157e^-(t/4)
=-39+157/4 e^(-t/4)
thus the velocity at h=0 will be as follows:
at h=0, the value of t will be:
0=400-39t-157e^(-t/4)
solving for t we get:
t=-5.4 or t=10.1
since we don't have negative time, t=10.1
thus the velocity at this point will be:
dh/dt=-38+1/4*157e^(-10.1/4)
=-38.86 sec
this means that the object dropped by a velocity of 38.86 sec</span>
Answer:
64
Step-by-step explanation:
4³ = 4 · 4 · 4
4 · 4 · 4
16 · 4
64
12*6 = 72 - (3*4) = 60 - (4*5) = 40
Step-by-step explanation:
point 1 ( -7,y)
point 2 (1,13)
y = 7
Answer: 6
Step-by-step explanation:
