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aliina [53]
2 years ago
7

Find the equation of the tangent line to the curve 2exy=x+y at (0,2).

Mathematics
1 answer:
DiKsa [7]2 years ago
8 0

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function  = f(x,y) = 2e^{xy} -x-y=0   ...(i)

Differentiating equation (i) with respective to 'x' , we get

2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0

apply  formula

\frac{d}{dx} (UV) = UV^{l} +V U^{l}

<u><em>step(ii):-</em></u>

⇒   2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0

⇒ 2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0

Taking common d y/d x

(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))

\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}

put At (0,2)

\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3

slope of the curve m = 3

<u><em>Step(iii)</em></u>:-

The equation of the tangent line to the curve

y-y_{1} =m(x-x_{1} )

y - 2 = 3 ( x - 0 )

3 x - y = 2

<u><em>Final answer:-</em></u>

The equation of the tangent line to the curve

3 x - y = 2

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