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amid [387]
3 years ago
5

Help!! 10 PTS!!

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
Two points of intersection are on the graph at (-1,7) and (1,3).
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Show that the following argument with hypotheses on lines 1–2 and conclusion on line c is
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Answer:

Step-by-step explanation:

p \Rightarrow q \equiv (\neg p \vee q) [logical equivalence]

\neg (q \vee r) \equiv (\neg q \wedge \neg r) [morgan laws]

if (\neg q \wedge \neg r) is true, then \neg q is true and \neg r is too.

with \neg q true, then q is false [double denial]

In the first equivalence it follows that \neg p is true [identity law]

Then it can be concluded that \neg p

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4 = numerator

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The circle below is centered at (3, 1) and has a radius of 2. What is its
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